# How To Write An Equation For A Vertical Line

Use the afterward definitions, theorems, and backdrop to break the problems independent in this Chapter.

We address (displaystyle lim _{xto a}f(x)=L) and say “the absolute of (f(x)text{,}) as (x) approaches (atext{,}) equals (L)” if it is accessible to accomplish the ethics of (f(x)) arbitrarily abutting to (L) by demography (x) to be abundantly abutting to (atext{.})

Let (f) be a action authentic on some accessible breach that contains (atext{,}) except possibly at (a) itself. Again we say that the absolute of (f(x)) as (x) approaches (a) is (Ltext{,}) and we address (displaystyle lim _{xto a}f(x)=L) if for every cardinal (varepsilon >0) there is a (delta >0) such that (|f(x)-L|lt varepsilon) whenever (0lt |x-a|lt deltatext{.})

(displaystyle displaystyle lim _{xto a}f(x)=LLeftrightarrow (lim _{xto a^-}f(x)=Lmbox{ and } lim _{xto a^ }f(x)=L))

Let (f) be a action authentic on a neighbourhood of (atext{,}) except possibly at (a) itself. Again (displaystyle lim _{xto a}f(x)=infty) agency that the ethics of (f(x)) can be fabricated arbitrarily ample by demography (x) abundantly abutting to (atext{,}) but not according to (atext{.})

The band (x=a) is alleged a vertical asymptote of the ambit (y=f(x)) if at atomic one of the afterward statements is true:

begin{equation*} begin{array}{lll} displaystyle lim _{xto a}f(x)=infty amp displaystyle lim _{xto a^-}f(x)=displaystyle infty amp displaystyle lim _{xto a^ }f(x)=infty \ displaystyle lim _{xto a}f(x)=-infty amp displaystyle lim _{xto a^-}f(x)=-infty amp displaystyle lim _{xto a^ }f(x)=-infty end{array} end{equation*}

Let (f) be a action authentic on ((a,infty )text{.}) Again (displaystyle lim _{xto infty }f(x)=L) agency that the ethics of (f(x)) can be fabricated arbitrarily abutting to (L) by demography (x) abundantly large.

The band (y=a) is alleged a accumbent asymptote of the ambit (y=f(x)) if if at atomic one of the afterward statements is true:

begin{equation*} lim _{xto infty }f(x)=a mbox{ or } lim _{xto -infty }f(x)=atext{.} end{equation*}

Let (c) be a connected and let the banned (displaystyle lim _{xto a}f(x)) and (displaystyle lim _{xto a}g(x)) exist. Then

(displaystyle displaystyle lim _{xto a}(f(x)pm g(x))=lim _{xto a}f(x)pmlim _{xto a}g(x))

(displaystyle displaystyle lim _{xto a}(ccdot f(x))=ccdot lim _{xto a}f(x))

(displaystyle displaystyle lim _{xto a}(f(x)cdot g(x))=lim _{xto a}f(x)cdot lim _{xto a}g(x))

(displaystyle lim _{xto a}frac{f(x)}{g(x)}=frac{lim _{xto a}f(x)}{lim _{xto a}g(x)}) if (lim _{xto a}g(x)not= 0text{.})

If (f(x)leq g(x)leq h(x)) back (x) is abreast (a) (except possibly at (a)) and (displaystyle lim _{xto a}f(x)=lim _{xto a}h(x)=L) again (displaystyle lim _{xto a}g(x)=Ltext{.})

(displaystyle lim_{theta to 0}frac{sin{theta}}{theta}=1) and (displaystyle lim_{theta to 0}frac{cos{theta}-1}{theta}=0text{.})

(displaystyle lim_{x to 0}(1 x)^{frac{1}{x}}=e) and (displaystyle lim_{x to infty }left( 1 frac{1}{x}right) ^x=etext{.})

Suppose that (f) and (g) are differentiable and (g'(x)not= 0) abreast (a) (except possibly at (atext{.})) Suppose that (ds lim _{xto a}f(x)=0) and (ds lim _{xto a}g(x)=0) or that (ds lim _{xto a}f(x)=pm infty) and (ds lim _{xto a}g(x)=pm inftytext{.}) Again (ds lim _{xto a}frac{f(x)}{g(x)}=lim _{xto a}frac{f'(x)}{g'(x)}) if the absolute on the appropriate ancillary exists (or is (infty) or (-infty)).

We say that a action (f) is connected at a cardinal (a) if (displaystyle lim _{xto a}f(x)=f(a)text{.})

If (f) is connected at (b) and (displaystyle lim _{xto a}g(x)=b) again (displaystyle lim _{xto a}f(g(x))=f(lim _{xto a}g(x))=f(b)text{.})

Let (f) be connected on the bankrupt breach ([a,b]) and let (f(a)not= f(b)text{.}) For any cardinal (M) amid (f(a)) and (f(b)) there exists a cardinal (c) in ((a,b)) such that (f(c)=Mtext{.})

How To Write An Equation For A Vertical Line – How To Write An Equation For A Vertical Line
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